AI Article Synopsis
- Solid KMnF reacts with excess SbF to form elemental F, but when the reaction occurs in anhydrous HF (aHF), a different product, K[(MnF)(SbF)]F, is formed instead.
- The synthesized compound was characterized using techniques like crystal structure analysis, Raman spectroscopy, and quantum-chemical calculations.
- The paper emphasizes the importance of using strictly anhydrous HF in reactions, and it discusses methods for effectively drying moist HF to achieve this.
Article Abstract
It is well established that solid KMnF reacts with excess SbF forming elemental F. However, if the reaction is carried out in anhydrous HF (aHF) as a solvent, this is surprisingly not the case. Instead, the green Mn(IV) compound K[(MnF)(SbF)]F is obtained. The reductive elimination of F was not observed under the applied conditions. The compound was characterized by its crystal structure, by Raman spectroscopy, and by quantum-chemical solid-state calculations. It crystallizes in the monoclinic space group 2/, 164, with the lattice parameters = 12.2393(13), = 12.167(2), = 20.115(5) Å, β = 110.805(8)°, = 2800.1(9) Å, = 4 at = 200 K. As the use of strictly anhydrous HF is crucial in this and other similar reactions, methods for drying moist HF are discussed.
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| http://dx.doi.org/10.1021/acs.inorgchem.4c00971 | DOI Listing |
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