A Se complex, Ph P, and (C Me ) are formed in the reduction of Se=PPh by the Nd complex [(C Me ) Nd] [Eq. (a)]. The latter is thus reminiscent of [(C Me ) Sm], which, however, appears to be a stronger reductant than [(C Me ) Nd]. This suggests that the reductive reactivity of [(C Me ) Ln] complexes can be tuned by varying the size of the metal atom.
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