AI Article Synopsis
- The reduction of [Cp*Fe(η-E)] with lanthanide reagents typically results in bond formation between the lanthanide and the element E (either phosphorus or arsenic).
- Using the bulky reagent [(DippForm)Sm(thf)] instead leads to the opening of the thf ring and subsequent reduction of the polypnictide.
- This process creates new 3d/4f polyphosphide or polyarsenide complexes where the bulky reagent and the iron complex are connected through a thf-derived structure, without forming a lanthanide-element bond.
Article Abstract
Reduction of [Cp*Fe(η-E)] (E = P, As) with divalent lanthanide reagents usually leads to reduction of [Cp*Fe(η-E)] followed by a Ln-E bond formation. In contrast, by using the sterically encumbered reagent [(DippForm)Sm(thf)] (DippForm = {(2,6-PrCH)NC(H)[double bond, length as m-dash]N(2,6-PrCH)}), ring-opening of thf and reduction of the polypnictide is observed. This leads to two new 3d/4f polyphosphide or polyarsenide complexes [(DippForm)Sm(Cp*Fe)E{(CH)O}{(DippForm)Sm(thf)}], in which [(DippForm)Sm(thf)] and [Cp*Fe(η-E)] are linked by a ring-opened thf molecule and no Ln-E bond formation is observed.
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| http://dx.doi.org/10.1039/c6cc07367k | DOI Listing |
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