AI Article Synopsis
- Monovalent RAl reacts with E2Et4 (E=Sb, Bi) to form RAl(EEt2)2 by inserting into the weak E-E bond.
- The reactions of RGa with E2Et4 generate an equilibrium between RGa(EEt2)2 and starting materials, which is influenced by temperature.
- RIn does not react with Sb2Et4 but does form RIn(BiEt2)2 when reacting with Bi2Et4 at low temperatures.
Article Abstract
Monovalent RAl (R=HC[C(Me)N(2,6-iPr2C6H3)]2) reacts with E2Et4 (E=Sb, Bi) with insertion into the weak E-E bond and subsequent formation of RAl(EEt2)2 (E=Sb 1; Bi 2). The analogous reactions of RGa with E2Et4 yield a temperature-dependent equilibrium between RGa(EEt2)2 (E=Sb 3; Bi 4) and the starting reagents. RIn does not interact with Sb2Et4 under various reaction conditions, but formation of RIn(BiEt2)2 (5) was observed in the reaction with Bi2Et4 at low temperature.
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| http://dx.doi.org/10.1002/anie.201406304 | DOI Listing |
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