AI Article Synopsis

  • Crystals of the compound C(15)H(12)N(4)O·H(2)O were formed through a reaction between isonicotinylhydrazine and 3-indolylformaldehyde.
  • The molecule has an E configuration, with the isonicotinoylhydrazine and indole parts positioned on opposite sides of the C=N double bond.
  • The crystal structure features a twisted pyridine ring in relation to the indole ring, with a dihedral angle of 44.72° and includes various hydrogen bonding interactions.

Article Abstract

Crystals of the title compound, C(15)H(12)N(4)O·H(2)O, were obtained from a condensation reaction of isonicotinylhydrazine and 3-indolylformaldehyde. The mol-ecule assumes an E configuration, with the isonicotinoylhydrazine and indole units located on the opposite sites of the C=N double bond. In the mol-ecular structure the pyridine ring is twisted with respect to the indole ring system, forming a dihedral angle of 44.72 (7)°. Extensive classical N-H⋯N, N-H⋯O, O-H⋯O and O-H⋯N hydrogen bonding and weak C-H⋯O inter-actions are present in the crystal structure.

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http://www.ncbi.nlm.nih.gov/pmc/articles/PMC2977231PMC
http://dx.doi.org/10.1107/S1600536809027329DOI Listing

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The title compound, C(12)H(12)N(3)O(2) (+)·Cl(-)·H(2)O, was prepared by the reaction of N'-[(5-methyl-2-fur-yl)methyl-ene]isonicotino-hydrazide and hydro-chloric acid at room temperature. The entire molecule is approximately planar with a maximum deviation of 0.047 (2) Å.

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Article Synopsis
  • Crystals of the compound C(15)H(12)N(4)O·H(2)O were formed through a reaction between isonicotinylhydrazine and 3-indolylformaldehyde.
  • The molecule has an E configuration, with the isonicotinoylhydrazine and indole parts positioned on opposite sides of the C=N double bond.
  • The crystal structure features a twisted pyridine ring in relation to the indole ring, with a dihedral angle of 44.72° and includes various hydrogen bonding interactions.
View Article and Find Full Text PDF

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