The title compound, C(15)H(13)NO(3), crystallizes with three independent mol-ecules per asymmetric unit (Z' = 3). One of these mol-ecules is found to have a configuration with a greater twist between its two aromatic rings than the other two [compare 70.26 (13) and 72.
View Article and Find Full Text PDFThe title compound, C(14)H(12)O(2), has an essentially planar conformation with the two aromatic rings forming a dihedral angle of 5.23 (9)° and the aldehyde group lying in the plane of its aromatic group [maximum deviation = 0.204 (3) Å].
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